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What is the inverse function of y = x + 1
Its inverse function is y = X-1
It is known that o.a.b.c is four points on the same straight line, the distance between AB is L1, and the distance between BC is L2. An object starts from o point and moves uniformly along the straight line and passes through three points a.b.c. it is known that the time taken for an object to pass through segment AB and segment BC is equal?
According to △ s = at ^ 2: (l2-l1) / a = t (a to b) ^ 2, the speed of passing point B is (L1 + L2) / 2T (a to b), so the time from O to B is (L1 + L2) / [2T (a to B) a], and the distance from O to B is
The moving friction coefficient between the object and the inclined plane is 0.1. The acceleration of gravity is 10 m / S 2. How much work does gravity do to the object? How much work does the sliding friction force do to the object? How much work does the support force do to the object? How much work does the combined force do to the object? 30j-4j 0.26j)
1.W1=mgh=10×3=30J
2.W2=-μmgcosAl=0.1×10×(4/5)×5=-4J
3. There is no displacement in the direction of supporting force, and the work done is 0
4. Joint work: W3 = W1-W2 = 26j
When the train with mass m = 3 × 10 ^ 6 kg starts from stationary along the straight track with constant rated power, the resistance in the process of movement remains unchanged. After 1000 s, when the speed reaches the maximum driving speed of 72km / h, the driver knows that there is a landslide at 4km ahead and the track is damaged, he immediately applies the emergency brake, In case of emergency braking, the additional braking force of the locomotive is 9 × 10 ^ 4N. As a result, the train just reaches the track damage and stops (1) Acceleration of train during emergency braking (2) The resistance of the train in the process of running (3) Rated power of locomotive (4) Total distance of train movement
(1) According to 2As = V ^ 2, a = 0.05m/s ^ 2 (2) according to a = (F + fbraking) / m, f = 6 × 10 ^ 4N (3) constant rated power starting, that is, f = f traction V remains unchanged. Due to the gradual increase of speed, f traction decreases gradually until f traction = f reaches the maximum driving speed, so f = fvmax = 1.2 × 10 ^ 6W (4) according to kinetic energy
The following statement about motion synthesis and decomposition is wrong A. The time for the manager of the combined movement and the sub movement must be equal, that is, the joint movement and the sub movement start and end at the same time B. When a boat crosses a river at a constant speed, the size of the current velocity may affect the crossing time C. The oblique throwing motion can be regarded as the combination of uniform linear motion along initial velocity direction and free falling body movement along vertical direction D. The horizontal throwing motion can be regarded as the combined motion of uniform linear motion in horizontal direction and free falling body movement in vertical direction
BC
A I'm not going to explain the answer,
B the answer will not affect his crossing time, no matter what his direction is. As long as his vertical speed across the opposite bank does not change, it will not change. Because the direction of water velocity is perpendicular to the direction of normal vertical speed across the bank, so it is wrong
C the answer here should be the combination of horizontal uniform linear motion and vertical throw motion
D is right
When a car with a rated power of 8kw is driven on a straight road, the maximum mass selected is 20 meters per second, and the maximum mass is 2000 kg. If the car starts to move in a straight line with the superposition degree of 2 meters, and the resistance remains constant during the movement, the following can be obtained: constant resistance of the vehicle? Instantaneous power of the vehicle at the end of 3 seconds?
When the maximum speed of the car is the rated power, f is the minimum and equal to the resistance F
P = fvmax = fvmax
F = P / Vmax = 80000 / 20 = 4000N
2、F-f=ma
v=at
Instantaneous power = FV = (MA + F) at = (20 * 2 + 4000) * 2 * 3 = 24240 w
Mathematics book grade 5 Volume 1 (people's Education Press) exercise 3 all answers! 1. Count and compare. 42 ÷ 3= 91 ÷ 14= 4.2 ÷ 3= 9.1 ÷ 14= 2. There are four new fairy tales with a price of 26.8 yuan. How much is the average price per copy? 3. Class 5 (1) has a class fee of 24.2 yuan, and the students get 16.4 yuan from selling waste products. Xiao Ling: with this money, you can buy 7 copies of Juvenile Science and technology for small bookshelves Xiaoqiang: you can also buy 14 skipping ropes. Q: how much is a copy of juvenile technology? How much is a skipping rope? What else can you ask?? 4. On weekends, my father took Xiao Yong to mountain climbing. It was 7.2 kilometers from the mountain to the top of the mountain. It took them 3 hours to go up and 2 hours to go down. What is the speed of going up and down the mountain? What else can you ask? It's just not finished...
1. Calculate and compare
42 ÷ 3= 14 91 ÷ 14=6.5
4.2 ÷ 3= 1.4 9.1 ÷ 14=0.65
2. There are four new fairy tales with a price of 26.8 yuan. How much is the average price per copy?
26.4 △ 4 = 6.6 (yuan)
A: the average price is 6.6 yuan per copy
The postcode of the people's Education Press
Book Number: ISBN 978-7-107-18704-9 / c.11794 (course) address: Building 1, yard 17, Zhongguancun South Street, Haidian District, Beijing postcode: 100081 Building 1, yard 17, Zhongguancun South Street, Haidian District, Beijing
The fifth grade mathematics book (people's Education Press) 121 page 8 how to do? To write the process and find what!
1-1/2=1/2
1/2-1/3=1/6
1/3-1/4=1/12
1/4-1/5=1/20
If the denominator of two integers is 1, the denominator is 1
1/2+1/6+1/12+1/20
=1-1/2 +1/2-1/3 +1/3-1/4+1/4-1/5
=1-1/5
=4/5
Fifth grade second volume mathematics book, people's education press has the question not to be able to How many liters of water will seep out of a cuboid glass jar, 8dm long, 6dm wide, 4dm high, and 2.8dm deep
First calculate the volume of the cylinder: 8 * 6 * 4 = 192 (DM cube), then calculate the volume of water: 8 * 6 * 2.8 = 134.4 (DM cube), then calculate the volume of cube: 4 * 4 * 4 = 64 (DM cube), and finally calculate the overflow: 192-134.4 = 57.6 (DM's Cube) 64-57.6 = 6.4 (DN's Cube) = 6.4 (liter)
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RELATED INFORMATIONS
- 1. Fifth grade on the mathematics book (people's Education Press) exercise 18 how to write?
- 2. An object slides from the top of the slope at a constant speed, and the sliding acceleration is 2m / S2. If the object slides to the bottom, the sliding distance is 3% of the length of the slope 4. What is the slope length?
- 3. The rated power of a crane is 10kW. It is used to lift a 2.5 × 10 ^ 3kg steel beam. At first, the steel beam moves up uniformly with an acceleration of 0.2m/s? 2 for 1s, and then it moves at a constant speed after adjustment (1) The instantaneous power of pulling force at the end of 1s; (2) What is the maximum speed that the steel beam can reach when it rises? (g = 9.8 m / S 2)
- 4. The maximum speed of a vehicle with a rated power of 80kW can reach 20m / s when driving on a horizontal and straight road, and the mass of the vehicle is 2T. If the car starts to move in a straight line with constant resistance, the acceleration is 2 meters per second How long can the process of uniform acceleration be maintained? What is the real-time power of the last vehicle in 3.3 seconds? 4 how much work has been done by the automobile engine in the process of uniform acceleration? 3. It seems to be the fifth power of 48kW 4.2 * 10
- 5. As shown in the figure, it is a long enough inclined plane with a dip angle of θ = 37 ° and a mass of M = 10kg. Under the action of a force of F = 100 N along the inclined plane at the bottom of the inclined plane, the body moves from rest to 4m in 2S, and the force F is removed at the end of 2S, (sin 37 ° = 0.6, cos 37 ° = 0.8, 2) find: (1) the dynamic friction coefficient μ between the object and the inclined plane; (2) the velocity V of the object at the end of 1.5 s from the removal force F; (3) when the object passes 4.5 m away from the bottom of the slope
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- 15. Let y = f (x), y = g (x) have inverse functions, and the function images of F (x-1) and g-1 (X-2) are symmetric with respect to the straight line y = X. if G (5) = 1999, then f (4)=______ .
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