1 calculation question. (- 1 / 2 + 1 / 6 - 3 / 8 + 5 / 12) * - 24) = = 1= （-1/2 +1/6 -3/8 +5/12）* （-24） = = =

1 calculation question. (- 1 / 2 + 1 / 6 - 3 / 8 + 5 / 12) * - 24) = = 1= （-1/2 +1/6 -3/8 +5/12）* （-24） = = =

Original formula = (- 12 / 24 + 4 / 24-9 / 24 + 10 / 24) * - 24
=(-7/24)*(-24)
=7
X to 3 / 4 is 12 times 9 / 10 to solve the equation
X to 3 / 4 = 4x / 3
12 times 9 / 10 = 54 / 5
X = 54 / 5 times 3 divided by 4 = 8.1
It is known that Tan α = 1 / 2, Tan β = 1 / 3, and 0
tan(α+β)=(tanα+tanβ)/(1-tanαtanβ)=...=1
Zero
tan(a+b)=(tana+tanb)/(1-tana*tanb)=1
PI
Solution equation: 4 / 3-x = (x-3 / 5) - 1
4／3-X=（X／5-3）-1
It's time to get to the special
4／3-X=X／5-3-1
Transfer items and merge similar items
6X／5=16／3
When the coefficient is changed to 1, we get
X=40／9
20-15x=9-3x-20
x=-4/3
Think for yourself
4 / 3-x = (x-3 / 5) - 1
4 / 3-x = x-3 / 5-1
4 / 3-x = x-4 / 5
4 / 3 + 4 = x / 5 + X
16 / 3 = 6x / 5
X = 40 / 9
4/3-x=(x-3)/5-1
4/3-x=x/5-3/5-1
4/3-x=x/5-8/5
4/3+8/5=x/5+x
20/15+24/15=x/5+5x/5
44/15=6/5x
x=22/9
It is known that Tan α = 1 / 3
Calculate sin α + 2cos α / 5cos α - sin α, 1 / 2Sin α, cos α + cos square α
1. (Sina + 2cosa) / (5cosa Sina) = numerator denominator divided by cosa = (Tana + 2) / (5-tana) = 1 / 2; 2,1 / (2sinacosa + cos & sup2; a) = (Sin & sup2; a + cos & sup2; a) / (2sinacosa + cos & sup2; a) = numerator denominator divided by cos & sup2; a = (1 + Tan & sup2; a) / (2tana
4 / 5 (x + 1) = 16 solutions
4 out of 5 (x + 1) = 16
0.8x+0.8=16
8x+8=160
8x=152
x=19
I wish you a happy study!
X=19
0.8(x+1)=16 x=19
4/5(X+1)=16
0.8X +0.8 =16
0.8X =15.2
X =19
(X+1)=16x5/4
X+1=20
X=19
19。。。 Multiply both sides by 5 / 4 to get (x + 1) = 20, x = 19
4/5(x+1)=16
0.8(x+1)=16
x+1=20
x=19
Given that Tan (α - β / 2) = 1 / 2, Tan (β - α / 2) = - 1 / 3, then Tan ((α + β) / 2)=
tan((α+β)/2)
=tan(α-β/2+β-α/2)
=[(tan(α-β/2)+tan(β-α/2)]/[1-(tan(α-β/2)*tan(β-α/2)]
=(1/2-1/3)/(1+1/2*1/3)
=1/6/(7/6)
=1/7
X △ 2 / 3 = 4 / 5 △ 1 / 2 (solving the equation)
X divided by 2 / 3 = 4 / 5 * 2
X divided by 2 / 3 = 8 / 5
x=8/5*2/3
x=16/15
X △ 2 / 3 = 4 / 5 △ 1 / 2
3X/2=4/5x2
X=8/5x2/3
=16/15
2 / 3 = 4 / 5 / 2
X △ 2 / 3 = 8 / 5
X = 8 / 5 × 2 / 3
X = 16 / 15
x÷(2/3)=(4/5)÷(1/2)
x÷(2/3)=8/5
x=8/5*2/3
x=16/15
Given Tan α = 1 / 2, Tan β = 1 / 3, 0 < α < π / 2, π < β < 3 π / 2, what is the value of α + β?
5 / 4
Tan (a + b) = (Tana + tanb) / (1-tana * tanb) = (1 / 2 + 1 / 3) / (1-1 / 6) = 1 π
1 / 3 (x + 2) = 1 / 4 (x + 5) to solve the equation!
Open the brackets, and then add and subtract from the equation
1/3x+2/3=1/4x+5/4
4/12x-3/12x=15/12-8/12
1/12x=7/12
X=7