Ax + by = 3 ax square + by square = 7 ax cube + by cube = 16 ax fourth power + by fourth power = 42 ax fifth power + by fifth power =?

Ax + by = 3 ax square + by square = 7 ax cube + by cube = 16 ax fourth power + by fourth power = 42 ax fifth power + by fifth power =?

(AX ^ 2 + by ^ 2) (x + y) = ax ^ 3 + by ^ 3 + XY (AX + by), that is: 7 (x + y) = 16 + 3xy. (1) (AX ^ 3 + by ^ 3) (x + y) = ax ^ 4 + by ^ 4 + XY (AX ^ 2 + by ^ 2), that is: 16 (x + y) = 42 + 7xy. (2) the simultaneous equations of solution (1) (2) are as follows: (x + y) = - 14xy = - 38 (AX ^ 4 + by ^ 4) (x + y) = ax ^ 5 + by ^ 5 + XY (AX ^ 3 + by ^ 2)
A coordinates are (2,4) and B coordinates are (5,2). They satisfy the equation AX + by = 16 and find the value of (a-b) to the power of 2010
2a+4b=16
5a+2b=16
6a=16
a=8/3
b=8/3
a-b=0
0^2010=0
The coordinates of a are (2,4) and the coordinates of B are (5,2), which satisfy the equation AX + by = 16
2a+4b=16 5a+2b=16 a=2,b=3
a-b=-1
The power of (- 1) = 1
The system of equations can be obtained from the meaning of the problem
2a+4b=16
5a+2b=16
The solution is a = 2, B = 3
∴（a-b）^2010=(2-3)^2010=1
Substituting the two groups: 2A + 4B = 16, 5A + 2B = 16, a = 2, B = 3, the 2010 power of (a-b) is 1
Given: ax = by = CZ = 1, find the value of 11 + A4 + 11 + B4 + 11 + C4 + 11 + X4 + 11 + Y4 + 11 + Z4
According to the meaning of the title, we can get x = 1a, y = 1b, z = 1C, ｜ 11 + A4 + 11 + X4 = 11 + A4 + 11 + 1A4 = 11 + A4 + a4a4 + 1 = 1, similarly we can get: 11 + B4 + 11 + Y4 = 1; 11 + C4 + 11 + Z4 = 1, ｜ 11 + A4 + 11 + B4 + 11 + C4 + 11 + X4 + 11 + Y4 + 11 + Z4 = 3
The range of the function y = (x squared-4)
y=1/(x²-4)
x²-4≠0 y≠0
x²=1/y+4≥0
y(1+4y)≥0
Y ＞ 0 or Y ≤ - 1 / 4
On the inequality of solution about X, two thirds of X - three thirds of X is greater than or equal to 1 (a is not equal to 0)
The range of the function y = x square + X + 1 is?
Because the function is y = ax ^ 2 + BX + C,
Y = (4ac-b ^ 2) / 4A = 3 / 4, so the minimum value of Y is 3 / 4
So the range of Y is greater than 3 / 4
I don't know, right? Let's see --
Negative infinity to positive infinity
Y is not equal to - 1
On the inequality of X for the solution of mathematics problem in grade one of junior high school
(1) in the process of solving the above problems, the basis of the first step is: (2) in the process of solving the above problems, From which step does the error begin? Please write the code of the step. (3) the reason for the error is (4) what is the correct conclusion of this question
Hey, hey If your equation is written like this: 2 / 3x-1 = x / 3 + A-1, then the answer of a is 0, go to the denominator and multiply by 3 to get: 2x-3 = 2 + 3a-1, and then substitute x = 2 to get zero
The range of the function y = x square + x square + 1 / 1 + 1 is
Y = x & # 178; + 1 / (X & # 178; + 1) + 1 = (X & # 178; + 1) + 1 / (X & # 178; + 1) let X & # 178; + 1 = t, the square term is constant and nonnegative, X & # 178; ≥ 0, X & # 178; + 1 ≥ 1, t ≥ 1y = t + 1 / T. from the mean inequality, when t = 1 / T, that is, when t = 1, that is, when x = 0, y has the minimum value, and the range of function is [2, + ∞)
2 to positive infinity
The solution set of square + BX + C > 0 of inequality ax is {XL-1}
The solution set of inequality ax & # 178; + BX + C > 0 is {XL-1}
a(x²+1)+b(x-1)+c>2ax
ax²-2ax+a+b(x-1)+c>0
a(x-1)²+b(x-1)+c>0
By moving 1 unit to the right from y = ax & # 178; + BX + C > 0, y = a (x-1) &# 178; + B (x-1) + C can be obtained
So the solution set of a (X & # 178; + 1) + B (x-1) + C > 2aX is {xl0
3: The range of the function y = x square + X + 1 is?
Function y = 1 / (xsquare + X + 1)
t=x^2+x+1
=(x+1/2)^2+3/4≥3/4
Zero
Less than or equal to Four Thirds