The sum of all integer solutions of inequality system 1 / 2x + 1 > 0,1-x > 0 is

The sum of all integer solutions of inequality system 1 / 2x + 1 > 0,1-x > 0 is

Is it 1 / (2x) or (1 / 2) x? Suppose that the latter is - 1 + 0 = - 1
3x-0.6 in 0.2 = 2x-1.5-0.1 in 0.5 + 4.2
2x-1.5 of 0.5 is a term, x + 4.2 of 0.1 is a term, including what each step is for
3x-0.6 in 0.2 = 2x-1.5-0.1 in 0.5 + 4.2
Go to the denominator to sort out the items
15x-0.6=4x-1.5-10x+4.2
transposition
15x-4x+10x=0.6-1.5+4.2
Merge congeners
21x=3.3
Multiply both sides of the equation by 10, and change the integer
210x=33
x=33/210=11/70
The integer solution of inequality system X-1 ≤ 0 2x + 3 > 0 is
X-1.5 is - 1.5
Simplify (2x-5) (3x + 2) - 6 (x + 1) (X-2), where x = 0.2
(2x-5)(3x+2)-6(x+1)(x-2)
=6x²+4x-15x-10-6(x²+x-2x-2)
=6x²-11x-10-6(x²-x-2)
=6x²-11x-10-6x²+6x+12
= -5x+2
x=0.2
Original formula = - 5x0.2 + 2 = - 1 + 2 = 1
Finding the satisfaction inequality-11
-11
How to solve the equation that 0.3 parts 2x minus 0.6 parts (1.6 minus 3x) equals three parts (31x plus 8)
Solution to the system of inequalities: {3x + 4 / 5 ≤ 2,3x + 4 / 5 ＞ - 1
To solve the system of inequalities: {(3x + 4) / 5 ≤ 2, (3x + 4) / 5 ＞ - 1
The term 3x + 4 is less than or equal to 10
3x + 4 is greater than or equal to - 5
Solving the equation again, X is less than or equal to 3 and greater than or equal to - 3
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Let 0 be less than or equal to x, y, Z. verification: x + y + z-xy-yz-zx is less than or equal to 1
X+Y+Z-XY-YZ-ZX
=X(1-Y)+Y(1-Z)+Z(1-X)
1-y 1-z 1-z are all less than 0
So the result must be less than 0
Find the integer solution of inequality system − 1 ≤− 3x + 45 ≤ 2
We can get the inequality system − 1 ≤ − 3x + 45 − 3x + 45 ≤ 2, X ≤ 3 from (1), X ≥ - 2 from (2), and its solution set is - 2 ≤ x ≤ 3, so the integer solution of inequality system − 1 ≤ − 3x + 45 ≤ 2 is - 2, - 1, 0, 1, 2, 3
Given: x + y + Z = a, XY + YZ + ZX = B, then x ^ 2 + y ^ 2 + Z ^ 2 is equal to
x^2+y^2+z^2
=(x+y+z)^2-2*(xy+yz+zx)
=a^2-2b
a^2+2b
x^2+y^2+z^2=(x+y+z)^2-2(xy+yz+zx)=a^2-2b
The correct answer should be:
x^2+y^2+z^2
=(x+y+z)^2-2*(xy+yz+zx)
=a^2-2b
X + y + Z = 2 = x * 2 + y * 2 + Z * 2 + 2XY + 2yz + 2XZ = a * 2 and XY + YZ + XZ = B, then x * 2 + y * 2 + Z * 2 = a * 2-2b