Use the image of function to find the solution of the following equation x-3x + 2 = 0. You can take pictures or record the answers

Use the image of function to find the solution of the following equation x-3x + 2 = 0. You can take pictures or record the answers

y=x^2-3x+2=(x-3/2)^2-1/4x=1,x=2
The root of the equation 2y2-8y + 5 = 0 is not solved______ .
∵ a = 2, B = - 8, C = 5 ∵ △ = b2-4ac = 64-40 = 24 ∵ 0, the equation has two unequal real roots
Use the function image to find the solution of the following equation - x ^ 2 + 3x + 4 = 0, x ^ 2-x-2 = 0
Y = - x ^ 2 + 3x + 4 = - (x-4) (x + 1) the image is a parabola, the opening is downward, the axis of symmetry is: x = 3 / 2, passing through the point (0,4) (4,0) (- 1,0) and the vertex is (3 / 2,25 / 4) ‖ the solution is: x = 4 or x = - 1y = x ^ 2-x-2 = (X-2) (x-1) the image is a parabola, the opening is upward, the axis of symmetry is: x = 1 / 2, passing through the point (0, - 2
If 3x + 2Y = 54, 2x + 3Y = 56, then what are XY
3x+2y=54 (1)
2x+3y=56 （2）
(1)+(2)
5x+5y=110
x+y=22
So 3x + 3Y = 66 (3)
(3)-(1)
y=12
x=22-y=10
x=10,y=12
If 1 is multiplied by 3, 9x + 6y = 162
If 2 is multiplied by 2, 4x + 6y = 112
The difference is 5x = 50, x = 10
If we take in Formula 1, y = 12
3X+2Y=54
2X+3Y=56
6X+4Y=108
6X+9Y=168
5Y=60
Y=12
X=10
The recipe
3x + 2Y = 54 times 2 to get 6x + 4Y = 108 (1)
2X + 3Y = 56 times 3 to get 6x + 9y = 168 (2)
Subtract (1) from (2) to get 5Y = 60, y = 12, and then take y to (1) to get x = 10
X=10 Y=12
Let 3x + 2Y = 54 be a, let 2x + 3Y = 56 be B, A-B be X-Y = - 2, so x = Y-2 brings x = - Y-2 into a
We get y = 12, so x = 10
3x + 2Y = 54 (1) (1) * 3, 9x + 6y = 162 (3) (3) - (4), 5x = 50, x = 10 generations
2X + 3Y = 56 (2) (2) * 24x + 6y = 112 (4) x = 10 (1)
3x + 2Y = 54,2x + 3Y = 56 add 5x + 5Y = 54 + 56 5 (x + y) = 110 x + y = 22 3x + 3Y = 3 * 22 = 66 subtract the original two equations respectively, so x = 10, y = 12, x = 10, y = 12
Given that the images of power functions y = f (x) and y = g (x) pass through points (3,9) and (8,2), the solution set of inequality f (x) > G (x) is
F (x) = x ^ A, substituting (3,9) to get: 3 ^ a = 9, so: a = 2; so: F (x) = x & # 178;; G (x) = x ^ A, substituting (8,2) to get: 8 ^ a = 2, so: a = 1 / 3; so: G (x) = x ^ (1 / 3); f (x) > G (x), that is: X & # 178; > x ^ (1 / 3); from the image of power function, the solution set is (1, + ∞); if you don't understand
Given that the images of power functions y = f (x) and y = g (x) pass through points (3,9) and (8,2), the solution set of inequality f (x) > G (x) is 5 days and 15 hours from the end of the problem|
If 3x + 2Y = 54,2x + 3Y = 46, then x + y = ()
x=() y=()
3x+2y=54,
2x+3y=46,
Then x + y = (54 + 46) / 5 = 20
x=14
Y=6
Twenty
x=( 10 ) y=( 12 )
X+Y=22
14 senior three
(54+46)/5=20
Twenty
X=10,Y=12,X+Y=22
If the power function f (x) = XA is known to pass through points (12,22), then the solution set of the inequality f (| x |) ≤ 2 is______ .
∵ the power function f (x) = XA's image passes through (12, 22); (12) α = 22, the solution is α = 12, the function f (x) = X12; the inequality f (| x |) ≤ 2 can be reduced to | x | 12 ≤ 2, that is | x | ≤ 2; the solution is | x | ≤ 4, that is - 4 ≤ x ≤ 4; the solution set of the inequality is {x | - 4 ≤ x ≤ 4}. So the answer is: {x | - 4 ≤ x ≤ 4}
To solve the system of equations x + y + Z = 2 x-2y + Z = - 1 x + 2Y + 3Z = - 1
From the first formula, we get x + Z = 2-y
The above formula is substituted into the second one
2-y-2y=-1
The solution is y = 1
So x + Z = 1
x=1-z
Substituting the above formula and y = 1 into the third formula, we get
1-z+2+3z=-1
The solution is Z = - 2
x=1-(-2)=3
The stability of the system of equations
X=3
Y=1
z=-2
Yes, x = 3; y = 1; Z = - 2
The first two equations use the elimination method to get y = 1, then the last two equations still use the elimination method to get z = - 2, and finally x = 3
X = 3, y = 1, z = - 2?
Given that f (x) = ax & # 178; + BX (a ≠ 0, B ≠ R), and y = f (x + 1) is an even function, the equation f (x) = x has two equal real roots, the analytic expression of function f (x) is obtained
The axis of symmetry of F (x + 1) is x = 0
F (x) shifts one unit to the left to get f (x + 1)
So the axis of symmetry of F (x) is x = 1
So - B / 2A = 1
We get B + 2A = 0
Equation f (x) = x
So ax ^ 2 + (B-1) x = 0
We get B-1 = 0
So B = 1, a = - 1 / 2
So the analytic expression of function f (x) is f (x) = - 0.5x ^ 2 + X
To solve the equations: X − 43 = y + 14 = Z + 25X − 2Y + 3Z = 30
X − 43 = y + 14 = Z + 25 (1) x − 2Y + 3Z = 30 (2). From (1), let x − 43 = y + 14 = Z + 25 = k, x = 3K + 4, y = 4k-1, z = 5k-2 be substituted into equation (2) to get 3K + 4-2 (4k-1) + 3 (5k-2) = 30, remove brackets to get 3K + 4-8k + 2 + 15k-6 = 30, and get k = 3, so x = 3 × 3 + 4 = 13, y = 4 × 3-1 = 11, z = 5 × 3-2 = 13. Therefore, the solution of this system of equations is x = 13y = 11z = 13