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把每一個都除以3,看餘數 9÷3餘數為0; 1÷3餘數為1; 4÷3餘數為1; 3÷3餘數為0; 40÷3餘數為1; 121÷3餘數為1 由兩個餘數為1的數,後都减1÷前都有一個倍數,即:n=(4-1)÷1=3;則有(121-1)÷40=3
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