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設最小的偶數為x,則可知其餘兩個相鄰的偶數為:x+2、x+4,∵三個連續偶數的和是66,∴x+(x+2)+(x+4)=66,解方程得:x=20,即x+2=22,x+4=24.所以這三個偶數為:20、22、24.
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