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1)等邊三角形內有一個等腰三角形 ∠1=∠2=30,∠3=∠4=30 ∠5=180-(∠2+∠3)=180-(30+30)=120 2)三角形內角和=(3-2)*180 四邊形內角和=(4-2)*180 五邊形內角和=(5-2)*180 六邊形內角和=(6-2)*180 發現 N邊形內角和=(N-2)*180
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