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A={x|x^2+3x+2=0}={-2,-1} 因為A包含於B 所以A⊆;B 而 B={x|x^2+(m+1)x+m=0}={-1,-m} 因為B已經包含了-1 所以 只能是-m = -2 即m=2,此時B={-1,-2}符合
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