先化簡再求值:-(x2+y2)+[-3xy-(x2-y2)],其中x=-1,y=2.

先化簡再求值:-(x2+y2)+[-3xy-(x2-y2)],其中x=-1,y=2.

原式=-x2-y2-3xy-x2+y2=-2x2-3xy,當x=-1,y=2時,原式=-2×(-1)2-3×(-1)×2=4.