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數軸上 離開原點的距離小於2的整數點有:1、-1、0這3個. 不大於2的正整數點的個數有:1、2這2個. 等於2的整數點的個數有:2、-2這2個. 囙此X、Y、Z分別是3、2、2 x+y+z = 3 + 2 + 2 = 7
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