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x²;-7x+12=0→(x-3)(x-4)=0→x=3或x=4 原命題:若x=3,則x^2-7x+12=0(真) 逆命題:若x^2-7x+12=0,則x=3(假) 否命題:若x≠3,則x^2-7x+12≠0(假) 逆否命題:若x^2-7x+12≠0,則x≠3(真)
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