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題目應該是A-2的絕對值與(b+1)^2是互為相反數.那麼:由相反數定義,A-2的絕對值+(b+1)^2=0.因為一個數的絕對值和平方都是大於等於零的,當他們相加為零時,則兩者皆為零.A=2,b=-1.b^a是1.a^3+ b^15=7
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