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設立方體的邊長為L,則正方體對案頭的壓強P=FS=GS=ρL3gL2=ρLg,甲乙對案頭的壓強相等,得ρ甲L甲g=ρ乙L乙g,所以L甲L乙=ρ乙ρ甲=23,甲、乙質量比m甲m乙=ρ甲L3甲ρ乙L3乙=32×2333=49.故答案為:4:9.
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