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原式=(x-1)/(x+1)(x+2)-6/(x-2)(x+1)-(x-10)/(x+2)(x-2) =[(x-1)(x-2)-6(x+2)-(x-10)(x+1)]/(x+1)(x+2)(x-2) =(x²;-3x+2-6x-12-x²;+9x+10)/(x+1)(x+2)(x-2) =0/(x+1)(x+2)(x-2) =0
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