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sin(n*90)
a(n+2)=an 特徵方程r²;=1 r1=1 r2=-1 an=A(r1)^n+B(r2)^n =A+B(-1)^n 帶入a1=a,a2=b A-B=a A+B=b A=(a+b)/2 B=(b-a)/2 所以 an=A+B(-1)^n=(a+b)/2 +(b-a)/2*(-1)^n
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