계단식 가감 문제 (3x & sup 3; - 12x) / (x & sup 2; - 2x) – (x & sup 3; - 4x) / (x & sup 2; + 2x)

계단식 가감 문제 (3x & sup 3; - 12x) / (x & sup 2; - 2x) – (x & sup 3; - 4x) / (x & sup 2; + 2x)

(3x & suup3; - 12x) / (x & 슈퍼 2; - 2x) – (x & 슈퍼 3; - 4x) / (x & 슈퍼 2; + + + 2x) = 3x (x & sup2; - 4) / (x & sup 2; - (x & sup2; - 2x - 2x) - x (x & sup2 (x & sup3) - (x & sup3) / (x x (x + 2) (x x (x + 2) / x (x (x x x (2)] / x (x (x (x x - 2) - (x (x - 2) - (x (x - 2) - x (x (x x x - 2) - (x x (x x x 2) - (x x x x x 2) - (x x x x x x x + 2 = 2 x + 8