Given that the solution of X − 1x + 2 − XX − 1 = m (x + 2) (x − 1) is negative, try to find the value range of M

Given that the solution of X − 1x + 2 − XX − 1 = m (x + 2) (x − 1) is negative, try to find the value range of M

To get: (x-1) 2-x (x + 2) = m, the solution is: x = 1 − M4, from the topic meaning: 1 − M4 < 0 and 1 − M4 ≠ - 2, and 1 − M4 ≠ 1, the solution is: M > 1 and m ≠ 9