已知x−1x+2−xx−1=m(x+2)(x−1)的解為負數,試求m的取值範圍.

已知x−1x+2−xx−1=m(x+2)(x−1)的解為負數,試求m的取值範圍.

去分母得:(x-1)2-x(x+2)=m,解得:x=1−m4,由題意得:1−m4<0且1−m4≠-2,且1−m4≠1,解得:m>1且m≠9.