Find the sequence 121212121212 The general term formula of

1212 = 1200 + 12 = 12 (1 + 100) 12121212 = 12 (1 + 100 + 10000 + 1000000) = 12 (1 + 102 + 104 + 106), then the nth term of the sequence is an = 12 (1 + 102 + 104 +...) +102n-2）=12×102n−1100−1=433(102n−1)．

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