Observe the following formula: 50 × 50 = 50 ^ 2-0 ^ 2 = 2500 49 × 51 = 50 ^ 2-1 ^ = 2499 48 × 52 = 50 ^ 2-2 ^ 2 = 2496: (50-N) (50 + n)= A 20 cm long wire is folded into a rectangle. How can it be folded to maximize the enclosed area? How many square centimeters is the maximum area?

Observe the following formula: 50 × 50 = 50 ^ 2-0 ^ 2 = 2500 49 × 51 = 50 ^ 2-1 ^ = 2499 48 × 52 = 50 ^ 2-2 ^ 2 = 2496: (50-N) (50 + n)= A 20 cm long wire is folded into a rectangle. How can it be folded to maximize the enclosed area? How many square centimeters is the maximum area?

50^2-n^2
The four sides are 5 cm, and the square has the largest area, 25 square cm