In the triangle ABC, CD is the height on the side of AB, ab = 13, BC = 12, AC = 5. Find the area of △ ABC

∵AC²＋BC²=5²＋12²=169=13²=AB²
Ψ Δ ABC is a right triangle, ∠ ACB = 90 °
The area of △ ABC = & frac12; × AC × BC = & frac12; × 5 × 12 = 30

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