In the triangle ABC, sin (a + b) + sin (a-b) = radical 6 / 2, cos (a + b) + cos (a-b) = radical 2 / 2, then B= Seek the process!

In the triangle ABC, sin (a + b) + sin (a-b) = radical 6 / 2, cos (a + b) + cos (a-b) = radical 2 / 2, then B= Seek the process!

sin(A+B)+sin(A-B)=sinAcosB+cosAsinB+sinAcosB-cosAsinB=√6/22sinAcosB=√6/2sinAcosB=√6/4 …… ①cos(A+B)+cos(A-B)=cosAcosB-sinAsinB+cosAcosB+sinAsinB=-√2/22cosAcosB=-√2/2cosAcosB=-√2/4 …… ② (1 / 2)