Inequality 1 / | 2x-3|
Obviously | 2x-3 | 0
Take 2x-3 on both sides|
2|2x-3|>1
|2x-3|>1/2
2x-31/2
x7/4
RELATED INFORMATIONS
- 1. 5x-20% = 19.2 find x
- 2. When x = 8.4, y = 6, the value of 9x-5y + 4x-8y
- 3. Solve the equation: 2x of 3 + 3x of 5 = 7 of 20
- 4. Factorization (2x-y) ^ 3 - (x-2y) ^ 3 - (x + y) ^ 3
- 5. If the monotone increasing interval of function f (x) = 1 / 3x ^ 3 + BX ^ 2 + 5x is (1,5), then the real number B is Can we get the value of B? Shouldn't we get the range?
- 6. If the tens of a three digit number are A-2, the single digit number is two times more than the ten digit number, and the hundred digit number is three times less than the single digit number, then the three digit number can be expressed as_______ ?
- 7. 5x = 17, the solution of the equation needs to be tested
- 8. Calculation of complement of original code and inverse code It is said in the book that the complement is the sign bit of the original code unchanged, and other changes, such as the original code 11100101 Inverse code 10011010 Complement 10011011 But why do many books actually write the inverse code of the above question as 00011010? I don't understand. Isn't that all changed? In a computer with 8-bit word length, the complement code is used, and the symbol bit occupies one bit, then - 128 is expressed as:_____ -The original code of 128 is 10000000, and its reverse code should not be 11111111. Why 011111? Is it not that the reverse code symbol bit remains unchanged, and the rest is reversed? I understand what you said above, which is the last sentence: why is there one more table number range complement? The reason is that in the complement, the true value 0 corresponds to only one code, while in the inverse code, the true value 0 corresponds to two codes. I don't quite understand why only one code corresponds to one more table number range than two codes? Sorry, please explain it to me again,
- 9. On the problems of discontinuities in Higher Mathematics f(x)=(1+x)/(1-x^2); X = - 1; X = 1; what kind of discontinuities are they; Let's talk about some ideas. In addition, this is just a question to fill in the blanks. I hope there will be a faster way to judge. Thank you
- 10. In anbn, A1 = 36, B1 = 64, A100 + B100 = 100, then the sum of the first 200 items of anbn is
- 11. Given x ^ 2 + x = - 1, find the value of x ^ 2009 + x ^ 2008 +. + x ^ 2 + X + 1
- 12. If the point m is on the circle C1: x2 + y2 = 1 and the point n is on the circle C2: x2 + y2-6x-8y + 21 = 0, then the value range of Mn is 0
- 13. Given Sina + cosa = m, Sina * cosa = n, try to determine the relationship between M and n RT. there needs to be a process,
- 14. The main problem I don't understand is that ad is not the middle line, and I can't get a picture. What picture is required to be drawn on the title? In the process of solving problem (2), have you found the method of "knowing the middle line on one side and the other side of the triangle, finding the length range of the third side"? If so, please solve the following problem: in △ ABC, AC = 5, middle line ad = 7, draw a picture and determine the length range of AB side
- 15. Isosceles trapezoid ABCD ad is parallel to bcae and perpendicular to bcae = 4AD Ad: BC In general, the ad on the top of the ladder is shorter, and the BC on the bottom is longer AB makes vertical reconnection with AC at left DC and right point a Another condition is AC = BC
- 16. It is known that the length of the side edge of the regular triangular prism abc-a1b1c1 is equal to the length of the side edge of the bottom, then the sine of the angle between Ab1 and acc1a1 is equal to () A. 64B. 104C. 22D. 32
- 17. Given that P1 (2, - 1), P2 (- 1,3), P is on the straight line p1p2, and the vector | p1p | = 2 / 3 | PP2 | There should be two points!
- 18. It is known that in isosceles trapezoid ABCD, ad is parallel to BC, ab = CD, the parallel line of AC passing through point d intersects the extension line of BA at point E, if ad = 3, BC = 7 Finding the area of trapezoid ABCD o .. There is also an AC vertical BD
- 19. As shown in the figure, AB is the diameter, there are points c and D on the semicircle arc, and arc AC = arc CB, arc ad = arc DC, connect BD AC to point P, and find PD: Pb Tomorrow is the test
- 20. Let P (P + 1) + 22 be all prime numbers of a complete square, and p be______ .