Isosceles trapezoid ABCD ad is parallel to bcae and perpendicular to bcae = 4AD Ad: BC In general, the ad on the top of the ladder is shorter, and the BC on the bottom is longer AB makes vertical reconnection with AC at left DC and right point a Another condition is AC = BC

Isosceles trapezoid ABCD ad is parallel to bcae and perpendicular to bcae = 4AD Ad: BC In general, the ad on the top of the ladder is shorter, and the BC on the bottom is longer AB makes vertical reconnection with AC at left DC and right point a Another condition is AC = BC

There is no solution
The results show that DF is perpendicular to BC, the perpendicular foot is f, the proportion of rectangular aefd is fixed, and the two inner angles of isosceles trapezoid are 0 ~ 180, ad: BC has no solution
Answer after supplement:
Let ad = 1, then AE = 4, let be = CF = x, from AC = BC, AC = 2x + 1
AE ^ 2 + EC ^ 2 = AC ^ 2 in right triangle AEC
In, 4 ^ 2 + (1 + x) ^ 2 = (2x + 1) ^ 2
The solution is x = 2 or x = - 8 / 3
So BC = 2x + 1 = 5
AD:BC=1:5