With 0, 1, 2, 3, you can set up () different even numbers

If the last digit is 0,
So there are 3 * 2 * 1 = 6
If the last digit is 2,
Because the thousand bits cannot be 0,
So there are 2 * 2 * 1 = 4,
There are altogether 6 + 4 = 10 different even numbers of four digits
If you still have doubts, please ask. I wish you progress in your study!

RELATED INFORMATIONS

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