Starting from 2, continuous even numbers are added. The sum of them is shown in the following table Sum of addends (s) 1 2=1×2 2 2+4+6=2*3 3 2+4+6=12=3*4 4 2+4+6+8=20=4*5 5 2+4+6+8+10=30=5*6 According to the law of the above question: 102 + 104 + 106 + +The value of 2002 (writing process required)

Starting from 2, continuous even numbers are added. The sum of them is shown in the following table Sum of addends (s) 1 2=1×2 2 2+4+6=2*3 3 2+4+6=12=3*4 4 2+4+6+8=20=4*5 5 2+4+6+8+10=30=5*6 According to the law of the above question: 102 + 104 + 106 + +The value of 2002 (writing process required)

2+4+6…… +2002=1003002=1001*1002
2+4+6…… +100=2550=50*51
102+104+106+…… +2002=(2+4+6…… +2002)-(2+4+6…… +100)=1003002-2550=1000452