As shown in the figure, given that FC is parallel to AB, parallel to de, angle 3: angle D: angle B = 2:3:4, calculate the degree of angle 3, angle B and angle D

3: ∠ D: ∠ B = 2:3:4 ∠ d = 1.5 ∠ 3 ∠ B = 2 ∠ 3fc parallel ab ∠ 2 + ∠ B = 180 ∠ 2 + 2 ∠ 3 = 180fc parallel de ∠ 1 + ∠ d = 180 ∠ 1 + 1.5 ∠ 3 = 180 ∠ 2 + 2 ∠ 3 + ∠ 1 + 1.5 ∠ 3 = 360 (∠ 1 + ∠ 2 + 3) + 2.5 ∠ 3 = 360 180 + 2.5 ∠ 3 = 360 ∠ 3 = 72 ∠ d = 108 ∠ B = 144

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