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A mathematical problem, requires detailed explanation A bucket of water is poured out for the first time, one sixth of which is poured out for the second time, one third for the last time, and one fourth for the last time. At this time, the water belt bucket is 20 kg, and the weight of the bucket is 5 kg. How many kg of water are there in the bucket at the beginning? A 50 B 80 C 100 D 36
1 / 6 + 1 / 3 + 1 / 4 = 3 / 4
The remaining 1-3 / 4 = 1 / 4
The barrel weighs 5 kg
There are 20 kilos left
So there's water, 20-5 = 15 kg
So the original water 15 △ 1 / 4 = 60kg
Choose?
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