As shown in the figure, known quadrilateral ABCD is diamond, de ⊥ AB, DF ⊥ BC, please explain the quantitative relationship between be and BF

As shown in the figure, known quadrilateral ABCD is diamond, de ⊥ AB, DF ⊥ BC, please explain the quantitative relationship between be and BF

EB = BF. In △ ade and △ CDF, ∵ quadrilateral ABCD is rhombic, ∵ a = ≌ C, ad = CD. De ⊥ AB, DF ⊥ BC, ∵ AED = ≌ CFD = 90 ·. ≌ ade ≌ CDF. ≌ AE = cf. EB is equal to BF