ABCD is a square with side length of 4, e and F are the midpoint of AB and ad, GC is vertical to plane ABCD, GC is equal to 2, find the distance from B to plane EFG?

AC BD to o EF AC to p
AC = 4 radical 2 CP = 3 radical 2
EF | BD so BD | EFG
So the distance from b o to EFG is equal
Make a perpendicular OQ from point O to Ag in ACG
OQ = distance from O to EFG
In triangle ACG OPQ,
OQ = 2 radical 11) / 11
B to EFG = 2 radical 11) / 11

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