P is a point in the square ABCD, and AP = 2. Rotate △ APB clockwise 60 ° around a to get △ AP ′ B ′. (1) make the rotated figure; (2) try to find the perimeter and area of △ app ′

(1) Δ AP ′ B ′ is shown in the figure; (2) by the nature of rotation, △ app ′ is an equilateral triangle with side length of 2, so the perimeter is 6 and the area is 12 × 2 × (2 × 32) = 3

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