Through the vertex a of parallelogram ABCD, make am ⊥ BC, an ⊥ CD, m and N are perpendicular feet. If ∠ man = 30 °, CD = 4cm, BC = 6cm, then am =? An =?

In the parallelogram ABCD, d = B, AB / / CD, AD / / BC
An ⊥ CD, am ⊥ BC,
So an ⊥ AB, am ⊥ ad
Therefore, BAM + man = - man + Dan = 90 degree
And ∠ man = 30 degree
Therefore, BAM = Dan = 60 degree
Am ⊥ BC, an ⊥ ab
From the law of right triangle
AM=1/2AB=2,AN=1/2AD=3

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