It is known that in the parallelogram ABCD, the diagonal lines AC and BD intersect at O, m and N, which are the midpoint of OA and OC respectively. What is the relationship between BM and DN?
BM = DN, DM is parallel to DN
From the parallelogram ABCD, Ao = Co, Bo = do are obtained
Because m and N are the midpoint of OA and OC respectively
So om = 0.5oa, OC = 0.5oc
So om = on
Because diagonal mob = nod
So triangle BOM is congruent with triangle don
So BM = DN, BMO = dno
So BM is parallel to DN