As shown in the figure: ab = AE, BC = ed ∠ B = ∠ E. verify that ∠ C = ∠ D is a Pentagon, and the counter clockwise letter is ABCDE
Connect AC, ad,
AB=AE,
∠B=∠E,
BC=ED ,
△ABC≌△AED,[SAS]
∠ACB=∠ADE,
AC=AD,
∠ACD=∠ADC,
∠ACB+∠ACD=∠ADE+∠ADC,
∠BCD=∠EDC,(∠C=∠D)
RELATED INFORMATIONS
- 1. In the pentagonal ABCDE, ∠ A is 135 ° AE ⊥ ed, ab ∥ CD, ∠ B = ∠ D, try to find the degree of ∠ C
- 2. AB = AE, BC = ed in Pentagon ABCDE Angle BCD = BAE = EDC = 120, is AC equal to ad AB = root 3 BC = 1
- 3. Known: as shown in the figure, in the Pentagon ABCDE, angle B = angle e = 90, ab = CD = AE = BC + de = 4 Finding the area of Pentagon
- 4. As shown in the figure, in the Pentagon ABCD, ab = CD = de = BC + AE = 2, angle B = angle e = 90 degrees, find the area of the Pentagon ABCD De Level is not enough, no picture
- 5. It is known that: as shown in the figure, in △ ABC, ∠ C = 90 °, cm ⊥ AB in M, at bisection ∠ BAC intersects cm in D, intersects BC in T, de ∥ AB through D intersects BC in E, verification: CT = be
- 6. It is known that: as shown in the figure, in △ ABC, ∠ C = 90 °, cm ⊥ AB in M, at bisection ∠ BAC intersects cm in D, intersects BC in T, de ∥ AB through D intersects BC in E, verification: CT = be
- 7. It is known that in the triangle ABC, D and E are points on AB and AC respectively, and de / / BC, be and CD intersect at point O, and the extension line of Ao intersects with BC at point M=
- 8. In the triangle ABC, D and E are the points on the sides of AB and AC respectively, and De is parallel to BC, be and DC intersect at O, and the line AO and BC intersect at M
- 9. As shown in the figure, in the parallelogram ABCD, AC and BD intersect at point O, and m and N are the midpoint of OA and OC respectively
- 10. It is known that in the parallelogram ABCD, the diagonal lines AC and BD intersect at O, m and N, which are the midpoint of OA and OC respectively. What is the relationship between BM and DN?
- 11. As shown in the figure, in the Pentagon ABCDE, BC = 4, CD = 4-ab, AE = de = 6, AE ⊥ AB, de ⊥ CD______ .
- 12. In the Pentagon ABCDE, if angle a = angle c = 90 degrees, ab = BC = de = AE + CD = 3, what is the area of the Pentagon?
- 13. As shown in the figure, ab = AE, BC = ed, ∠ B = ∠ e, AF ⊥ CD, foot drop is f, which means that AF bisects CD
- 14. It is known that ab = AE, BC = ed, AF is the vertical bisector of CD, as shown in the figure
- 15. As shown in the figure, in the pentagonal ABCDE, ∠ BAE = 120 °, ∠ B = ∠ e = 90 °, ab = BC, AE = De, find a point m and N on BC and de respectively to minimize the perimeter of △ amn, then what is the degree of ∠ amn + ∠ anm
- 16. As shown in the figure, in the pentagonal ABCDE, ∠ BAE = 120 °, ∠ B = ∠ e = 90 °. AB = BC, AE = De, find a point m, N on BC, de respectively, so that the perimeter of △ amn is the smallest, then the degree of ∠ amn + ∠ anm is () why extend AB to a 'to make Ba' = AB, extend AE to a 'to make AE = EA' ', connect a'm, a'n, then the perimeter of △ amn is the smallest?
- 17. As shown in the figure, in the Pentagon ABCDE, BC = De, AE = DC, angle c = angle e, DM is perpendicular to AB and M is the midpoint of ab
- 18. As shown in the figure, in the regular pentagon ABCDE, ab = AE, BC = ed, angle B = angle e, and point F is the midpoint of CD
- 19. As shown in the figure, ab = AE, angle B = angle e, BC = ed, f is the midpoint of CD, and verify that AF is vertical to CD
- 20. As shown in the figure, ab = AE, BC = ed. ∠ B = ∠ E. f is the midpoint of CD. Explain the reason why AF ⊥ CD .A one 1 1 1 1 1 1 1 1 1 1 1 1 B 1 1 1 E 1 1 1 1 1 1 one hundred and eleven million one hundred and eleven thousand one hundred and eleven C F D