As shown in the figure, in the pentagonal ABCDE, ∠ BAE = 120 °, ∠ B = ∠ e = 90 °, ab = BC, AE = De, find a point m and N on BC and de respectively to minimize the perimeter of △ amn, then what is the degree of ∠ amn + ∠ anm

The intersection point of a'a '' and BC, ED is m and N, and the intersection point of a'a '' and BC, ED is m and N. the intersection point of a'a '' and BC, ED is m and N, and the intersection point of a'a '' and BC, ED is m and n

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1. It is known that ab = AE, BC = ed, AF is the vertical bisector of CD, as shown in the figure
2. As shown in the figure, ab = AE, BC = ed, ∠ B = ∠ e, AF ⊥ CD, foot drop is f, which means that AF bisects CD
3. In the Pentagon ABCDE, if angle a = angle c = 90 degrees, ab = BC = de = AE + CD = 3, what is the area of the Pentagon?
4. As shown in the figure, in the Pentagon ABCDE, BC = 4, CD = 4-ab, AE = de = 6, AE ⊥ AB, de ⊥ CD______ ．
5. As shown in the figure: ab = AE, BC = ed ∠ B = ∠ E. verify that ∠ C = ∠ D is a Pentagon, and the counter clockwise letter is ABCDE
6. In the pentagonal ABCDE, ∠ A is 135 ° AE ⊥ ed, ab ∥ CD, ∠ B = ∠ D, try to find the degree of ∠ C
7. AB = AE, BC = ed in Pentagon ABCDE Angle BCD = BAE = EDC = 120, is AC equal to ad AB = root 3 BC = 1
8. Known: as shown in the figure, in the Pentagon ABCDE, angle B = angle e = 90, ab = CD = AE = BC + de = 4 Finding the area of Pentagon
9. As shown in the figure, in the Pentagon ABCD, ab = CD = de = BC + AE = 2, angle B = angle e = 90 degrees, find the area of the Pentagon ABCD De Level is not enough, no picture
10. It is known that: as shown in the figure, in △ ABC, ∠ C = 90 °, cm ⊥ AB in M, at bisection ∠ BAC intersects cm in D, intersects BC in T, de ∥ AB through D intersects BC in E, verification: CT = be
11. As shown in the figure, in the pentagonal ABCDE, ∠ BAE = 120 °, ∠ B = ∠ e = 90 °. AB = BC, AE = De, find a point m, N on BC, de respectively, so that the perimeter of △ amn is the smallest, then the degree of ∠ amn + ∠ anm is () why extend AB to a 'to make Ba' = AB, extend AE to a 'to make AE = EA' ', connect a'm, a'n, then the perimeter of △ amn is the smallest?
12. As shown in the figure, in the Pentagon ABCDE, BC = De, AE = DC, angle c = angle e, DM is perpendicular to AB and M is the midpoint of ab
13. As shown in the figure, in the regular pentagon ABCDE, ab = AE, BC = ed, angle B = angle e, and point F is the midpoint of CD
14. As shown in the figure, ab = AE, angle B = angle e, BC = ed, f is the midpoint of CD, and verify that AF is vertical to CD
15. As shown in the figure, ab = AE, BC = ed. ∠ B = ∠ E. f is the midpoint of CD. Explain the reason why AF ⊥ CD .A one 1 1 1 1 1 1 1 1 1 1 1 1 B 1 1 1 E 1 1 1 1 1 1 one hundred and eleven million one hundred and eleven thousand one hundred and eleven C F D
16. As shown in the figure, the angle B = ∠ C = 90 °, M is a point on BC, and DM bisects ∠ ADC, am bisects ∠ DAB, proving: ad = CD + ab
17. In trapezoidal ABCD, ad is parallel to BC, triangle ADC is 2:3 than triangle ABC, and the connecting line of diagonal midpoint m and N is 10 cm Finish it today as soon as possible
18. In trapezoid ABCD, ab ‖ CD, ∠ ABC = 90 °, ab = 5, BC = 10, Tan ∠ ADC = 2. (1) find the length of DC; (2) e is a point inside the trapezoid, f is a point outside the trapezoid, if BF = De, ∠ FBC = ∠ CDE, try to judge the shape of △ ECF, and explain the reason. (3) under the condition of (2), if be ⊥ EC, be: EC = 4:3, find the length of de
19. In a trapezoid ABCD, AB is parallel to CD, angle BCD equals 90 degrees, AB equals 1, BC equals 2, Tan angle ADC equals 2, and E is a point in the trapezoid The angle EDC is equal to the angle FBC and De is equal to BF. Try to judge the shape of triangle ECF and prove your conclusion
20. In the trapezoid ABCD, AB / / DC, CE are bisectors of angle BCD, and CE is perpendicular to ad, de = 2ae. CE divides the trapezoid into two parts: S1 and S2. If S1 = 1, s is obtained Sorry, there's no picture S1 is a quadrilateral abce, S2 is a triangle ECD