As shown in the figure, in the isosceles trapezoid ABCD, ad ∥ BC, point E is the midpoint of BC side

It is proved that: ∵ quadrilateral ABCD is isosceles trapezoid, ∵ AB = DC, ∵ B = ∵ C. ∵ e is the midpoint of BC, ∵ be = CE. In △ Abe and △ DCE, ab = DC, ≌ B = ≌ CBE = CE, ≌ Abe ≌ DCE (SAS), ≌ AE = De

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1. As shown in the figure, in the right angle trapezoid ABCD, ad ‖ BC, ∠ C = 90 °, ad = 5, BC = 9, take a as the center, rotate waist AB clockwise 90 ° to AE, connect De, then the area of △ ade is equal to () A. 10B. 11C. 12D. 13
2. As shown in the figure, in the square ABCD, the diagonal AC and BD intersect at point E, AF bisects ∠ BAC, intersects BD at point F, and proves: EF + 12ac = ab
3. As shown in the figure, in rectangular ABCD, the diagonal lines AC and BD intersect at point O, AE bisects ∠ bad, BC intersects at point E. if ∠ CAE = 15 °, calculate the degree of ∠ BOE
4. As shown in the figure, in rectangular ABCD, the bisector of ∠ bad intersects BC at point E, and point O is the intersection of diagonals, and ∠ CAE = 15 °, then ∠ BOE=______ Degree
5. It is known that: as shown in the figure, the diagonal of rectangle ABCD intersects at O, AE bisects ∠ bad intersects BC at e, ∠ CAE = 15 °, then ∠ BOE=______ °．
6. As shown in the figure: given rectangular ABCD, AC and BD intersect at O, AE ‖ BD, de ‖ AC. verification: OE ⊥ ad
7. In rectangular ABCD, AC and BD intersect at point O, AE bisects the angle bad, and if the angle EAO = 15 °, calculate the degree of the angle BOE I can't give you a picture
8. In rectangular ABCD, diagonal lines AC and BD intersect at point O, AE bisects ∠ bad, AE intersects BC at point E. if ∠ CAE = 15 °, what is the degree of ∠ BOE?
9. As shown in the figure, in rectangular ABCD, AC and BD intersect at point O, AE bisects ∠ bad, BC intersects at E. if ∠ EAO = 15 °, then the degree of ∠ BOE is______ Degree
10. In rectangle ABCD, AC BD intersects with 0 AE bisector angle bad if ∠ EAO equals 15 degrees and BOE equals 15 degrees=
11. As shown in the figure, in isosceles trapezoid ABCD, ad ‖ BC. AB = DC, e is the midpoint of BC, connecting AE and De, proving: AE = De
12. As shown in the figure, in the isosceles trapezoid ABCD, e is the midpoint of the bottom BC, connecting AE and de
13. As shown in the figure, in the isosceles trapezoid ABCD, e is the midpoint of the bottom BC, connecting AE and de
14. Given that the quadrilateral ABCD is a square and E is a point in the square, △ ade is an equilateral triangle, find the degree of ∠ EBC
15. Taking one side CD of square ABCD as equilateral triangle CDE, then ∠ AEB=-----
16. As shown in the figure, if the quadrilateral ABCD is a square and △ CDE is an equilateral triangle, then ∠ AED=______ ，∠AEB=______ ．
17. Quadrilateral ABCD is a square, triangle CDE is an equilateral triangle. Find the degree of angle AEB I can't send the picture, but describe it. A square (adce in clockwise) is connected with an equilateral triangle Dec on the left
18. As shown in the figure, in the parallelogram ABCD, AE is perpendicular to BC and E, AF is perpendicular to CD and F, the angle BAE = 30 degrees, be = 2, CF = 1. 1) calculate the area of triangle ECD; 2) if ed and AF intersect g, calculate the length of eg
19. As shown in the figure above, e is a point on the extension line of the edge ab of the parallelogram ABCD, and de intersects BC with F. prove that the area of triangle ABF = the area of triangle efc The picture can't be transmitted
20. In a parallelogram ABCD, e is a point on the extension line of edge AB, and de intersects BC with F. it is proved that s △ ABF = s △ efc