As shown in the figure, in isosceles trapezoid ABCD, ad ‖ BC. AB = DC, e is the midpoint of BC, connecting AE and De, proving: AE = De
It is proved that: ∵ quadrilateral ABCD is isosceles trapezoid, ∵ AB = DC, ∵ B = ∵ C. ∵ e is the midpoint of BC, ∵ be = CE. In △ Abe and △ DCE, ab = DC, ≌ B = ≌ CBE = CE, ≌ Abe ≌ DCE (SAS) ≌ AE = De
RELATED INFORMATIONS
- 1. As shown in the figure, in the isosceles trapezoid ABCD, ad ∥ BC, point E is the midpoint of BC side
- 2. As shown in the figure, in the right angle trapezoid ABCD, ad ‖ BC, ∠ C = 90 °, ad = 5, BC = 9, take a as the center, rotate waist AB clockwise 90 ° to AE, connect De, then the area of △ ade is equal to () A. 10B. 11C. 12D. 13
- 3. As shown in the figure, in the square ABCD, the diagonal AC and BD intersect at point E, AF bisects ∠ BAC, intersects BD at point F, and proves: EF + 12ac = ab
- 4. As shown in the figure, in rectangular ABCD, the diagonal lines AC and BD intersect at point O, AE bisects ∠ bad, BC intersects at point E. if ∠ CAE = 15 °, calculate the degree of ∠ BOE
- 5. As shown in the figure, in rectangular ABCD, the bisector of ∠ bad intersects BC at point E, and point O is the intersection of diagonals, and ∠ CAE = 15 °, then ∠ BOE=______ Degree
- 6. It is known that: as shown in the figure, the diagonal of rectangle ABCD intersects at O, AE bisects ∠ bad intersects BC at e, ∠ CAE = 15 °, then ∠ BOE=______ °.
- 7. As shown in the figure: given rectangular ABCD, AC and BD intersect at O, AE ‖ BD, de ‖ AC. verification: OE ⊥ ad
- 8. In rectangular ABCD, AC and BD intersect at point O, AE bisects the angle bad, and if the angle EAO = 15 °, calculate the degree of the angle BOE I can't give you a picture
- 9. In rectangular ABCD, diagonal lines AC and BD intersect at point O, AE bisects ∠ bad, AE intersects BC at point E. if ∠ CAE = 15 °, what is the degree of ∠ BOE?
- 10. As shown in the figure, in rectangular ABCD, AC and BD intersect at point O, AE bisects ∠ bad, BC intersects at E. if ∠ EAO = 15 °, then the degree of ∠ BOE is______ Degree
- 11. As shown in the figure, in the isosceles trapezoid ABCD, e is the midpoint of the bottom BC, connecting AE and de
- 12. As shown in the figure, in the isosceles trapezoid ABCD, e is the midpoint of the bottom BC, connecting AE and de
- 13. Given that the quadrilateral ABCD is a square and E is a point in the square, △ ade is an equilateral triangle, find the degree of ∠ EBC
- 14. Taking one side CD of square ABCD as equilateral triangle CDE, then ∠ AEB=-----
- 15. As shown in the figure, if the quadrilateral ABCD is a square and △ CDE is an equilateral triangle, then ∠ AED=______ ,∠AEB=______ .
- 16. Quadrilateral ABCD is a square, triangle CDE is an equilateral triangle. Find the degree of angle AEB I can't send the picture, but describe it. A square (adce in clockwise) is connected with an equilateral triangle Dec on the left
- 17. As shown in the figure, in the parallelogram ABCD, AE is perpendicular to BC and E, AF is perpendicular to CD and F, the angle BAE = 30 degrees, be = 2, CF = 1. 1) calculate the area of triangle ECD; 2) if ed and AF intersect g, calculate the length of eg
- 18. As shown in the figure above, e is a point on the extension line of the edge ab of the parallelogram ABCD, and de intersects BC with F. prove that the area of triangle ABF = the area of triangle efc The picture can't be transmitted
- 19. In a parallelogram ABCD, e is a point on the extension line of edge AB, and de intersects BC with F. it is proved that s △ ABF = s △ efc
- 20. E is a point on the extension line of the edge ab of the parallelogram ABCD, and de intersects BC with F. it is proved that s △ ABF = s △ efc