As shown in the figure, in isosceles trapezoid ABCD, ad ‖ BC. AB = DC, e is the midpoint of BC, connecting AE and De, proving: AE = De

As shown in the figure, in isosceles trapezoid ABCD, ad ‖ BC. AB = DC, e is the midpoint of BC, connecting AE and De, proving: AE = De

It is proved that: ∵ quadrilateral ABCD is isosceles trapezoid, ∵ AB = DC, ∵ B = ∵ C. ∵ e is the midpoint of BC, ∵ be = CE. In △ Abe and △ DCE, ab = DC, ≌ B = ≌ CBE = CE, ≌ Abe ≌ DCE (SAS) ≌ AE = De