Given the parallelogram ABCD, take ad BC as the edge, make positive △ ade and positive △ BCF outside the parallelogram, connect BD and EF, and they intersect at O, and prove EO = fo, do = Bo There is no picture

Given the parallelogram ABCD, take ad BC as the edge, make positive △ ade and positive △ BCF outside the parallelogram, connect BD and EF, and they intersect at O, and prove EO = fo, do = Bo There is no picture

In parallelogram ABCD
AD‖BC
∴∠ADB=∠CBD
And ∵ ∠ ade = ∠ CBF = 60 °
∴∠EDO=∠FBO
In parallelogram ABCD
AD=BC
∴DE=BF
And ∵ ∠ BOF = ∠ doe
∴△BOF≌△DOE(AAS)
∴EO=FO,DO=BO