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Known X-Y = 2, x ^ 2Y ^ 2 = 4 (1) XY value (2) x ^ 2008 + x ^ 2009 value
If x ^ 2Y ^ 2 = 4, xy = 2 can be obtained. If (X-Y) ^ 2 = 4 = x ^ 2 + y ^ 2-2xy has X-Y = 2, xy = 2 can be obtained. Because when xy = - 2, x = 0 and y = 0 should be eliminated. When XY = 2, (x + y) ^ 2 = 12, x + y = plus or minus 2, the root sign 3 is brought into the solution to get x = root sign 3 + 1, y = 1-root sign 3 or (x = negative root sign 3 + 1, y = - root sign 3-1), so problem 2 = Simplification
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