Given that ab = 8cm, ad = 12cm, the area of triangle Abe and triangle ADF are respectively 13% of rectangle ABCD, the area of triangle AEF is calculated
12 × 8 = 96 (square centimeter), 96 × 13 = 32 (square centimeter), 32 × 2 △ 8 = 8 (centimeter), 32 × 2 △ 12 = 513 (centimeter), 12 × (12-8) × (8-513), = 12 × 4 × 83, = 513 (square centimeter), 96 - (32 + 32 + 513), = 96-6913, = 2623 (square centimeter)
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- 1. Given that ab = 8cm, ad = 12cm, the area of triangle Abe and triangle ADF are respectively 13% of rectangle ABCD, the area of triangle AEF is calculated
- 2. It is known that ab = 8 cm, ad = 12 cm, the area of triangle Abe and triangle ADF are respectively One third of the rectangle ab-cd, find the area of triangle AEF
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- 6. As shown in the figure, the side length of square ABCD is 4, which is the midpoint of BC side, f is the point on DC side, and DF = 14dc, AE and BF intersect at G point. Find the area of △ ABG
- 7. As shown in the figure, ABCD is a square, point E is on BC, and DF ⊥ AE is on F. please determine a point G on AE to make △ ABG ≌ △ DAF, and explain the reason
- 8. In square ABCD, be = 3, EF = 5, DF = 4, how many degrees is the angle BAE + angle DCF?
- 9. As shown in the figure, in square ABCD, ab = 3, points E and F are on BC and CD respectively, and ∠ BAE = 30 ° and ∠ DAF = 15 ° to calculate the area of △ AEF
- 10. If f is any point on BC of square ABCD, AE bisects ∠ DAF intersecting CD and E, the proof is: AF = BF + De Can you get full marks in the senior high school entrance examination? You are only suitable for the analysis of filling in the blanks, but you will never get full marks for the answers. Now I'm sitting on the chair. What you did is wrong!
- 11. The quadrilateral ABCD is a square, and △ AEF is an equilateral triangle, where the points E and F are on BC and CD respectively. The detailed explanation of s △ CEF = s △ Abe + s △ ADF is obtained The area of s △ Abe and s △ ADF is equal to half ab. s △ CEF = half (a-b) 178; after that, how can we do it? We can't do it any more. Let's do it as soon as possible
- 12. If the areas of △ CEF, △ Abe and △ ADF are 3, 4 and 5 respectively, the area of △ AEF can be obtained
- 13. As shown in the figure, it is known that the quadrilateral ABCD is a square with a side length of 5cm. The area of the triangle ECF is 5 square centimeters larger than that of the triangle ADF. Find the length of the line CE
- 14. It is known that the quadrilateral ABCD is a square with a side length of 6 cm. The area of the triangle ECF is 3 square cm larger than that of the triangle ADF
- 15. In square ABCD, e and F are on BC and CD, respectively, ∠ EAF = 45 °, try to explain s △ AEF = s △ Abe + s △ ADF
- 16. As shown in the figure, in square ABCD, e and F are on BC and CD, respectively, ∠ EAF = 45 ° to prove s △ AEF = s △ Abe + s △ ADF
- 17. As shown in the figure, in square ABCD, e and F are on BC and CD, respectively, ∠ EAF = 45 ° to prove s △ AEF = s △ Abe + s △ ADF
- 18. As shown in the figure, ABCD is a rectangle, e and F are the points on BC and CD respectively, and s △ Abe = 3, s △ CEF = 2, s △ ADF = 2, then s △ AEF = ()
- 19. Rectangle ABCD, e and F are on BC and CD respectively. The area of triangle Abe, CEF and ADF are 2, 3 and 4 respectively
- 20. Let E and f be on the edge BC and CD of rectangular ABCD respectively, and the areas of △ Abe, △ ECF and △ FDA are a, B and C respectively. Find the area s of △ AEF