It is known that the quadrilateral ABCD is a square with a side length of 6 cm. The area of the triangle ECF is 3 square cm larger than that of the triangle ADF

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1. As shown in the figure, it is known that the quadrilateral ABCD is a square with a side length of 5cm. The area of the triangle ECF is 5 square centimeters larger than that of the triangle ADF. Find the length of the line CE
2. If the areas of △ CEF, △ Abe and △ ADF are 3, 4 and 5 respectively, the area of △ AEF can be obtained
3. The quadrilateral ABCD is a square, and △ AEF is an equilateral triangle, where the points E and F are on BC and CD respectively. The detailed explanation of s △ CEF = s △ Abe + s △ ADF is obtained The area of s △ Abe and s △ ADF is equal to half ab. s △ CEF = half (a-b) &# 178; after that, how can we do it? We can't do it any more. Let's do it as soon as possible
4. Given that ab = 8cm, ad = 12cm, the area of triangle Abe and triangle ADF are respectively 13% of rectangle ABCD, the area of triangle AEF is calculated
5. Given that ab = 8cm, ad = 12cm, the area of triangle Abe and triangle ADF are respectively 13% of rectangle ABCD, the area of triangle AEF is calculated
6. It is known that ab = 8 cm, ad = 12 cm, the area of triangle Abe and triangle ADF are respectively One third of the rectangle ab-cd, find the area of triangle AEF
7. If the perimeter of parallelogram ABCD is 44cm and ab is 2cm larger than ad, then AB is equal to?
8. In a parallelogram ABCD with an area of 15, if AB = 5, BC = 6, then CE + CF=
9. In the parallelogram ABCD, the diagonal lines AC and BD intersect at point O, if AC = 8, BD = 6 What is the value range of AB?
10. As shown in the figure, the side length of square ABCD is 4, which is the midpoint of BC side, f is the point on DC side, and DF = 14dc, AE and BF intersect at G point. Find the area of △ ABG
11. In square ABCD, e and F are on BC and CD, respectively, ∠ EAF = 45 °, try to explain s △ AEF = s △ Abe + s △ ADF
12. As shown in the figure, in square ABCD, e and F are on BC and CD, respectively, ∠ EAF = 45 ° to prove s △ AEF = s △ Abe + s △ ADF
13. As shown in the figure, in square ABCD, e and F are on BC and CD, respectively, ∠ EAF = 45 ° to prove s △ AEF = s △ Abe + s △ ADF
14. As shown in the figure, ABCD is a rectangle, e and F are the points on BC and CD respectively, and s △ Abe = 3, s △ CEF = 2, s △ ADF = 2, then s △ AEF = ()
15. Rectangle ABCD, e and F are on BC and CD respectively. The area of triangle Abe, CEF and ADF are 2, 3 and 4 respectively
16. Let E and f be on the edge BC and CD of rectangular ABCD respectively, and the areas of △ Abe, △ ECF and △ FDA are a, B and C respectively. Find the area s of △ AEF
17. As shown in the figure, in rectangular ABCD, e is the point on BC and F is the point on CD. Given s △ Abe = s △ ADF = 13sabcd, then the value of s △ AEF: s △ CEF is equal to () A. 2B. 3C. 4D. 5
18. In the isosceles trapezoid ABCD, ab ∥ DC, ad = BC = 5, DC = 7, ab = 13, point P starts from point a and moves to the midpoint C along ad → DC at the speed of 2 unit lengths per second At the same time, point Q starts from point B and moves along Ba to terminal a at the speed of 1 unit length per second. Let the movement time be T seconds (1) When the value of T is, the quadrilateral pqbc is a parallelogram (2) In the whole movement process, when t is the value, the quadrilateral with points B, C, P and Q as the vertex is isosceles trapezoid
19. Cut AE = BF = CG = DH on each side of square ABCD, connect AF, BG, CH and De, and intersect a ` B ` c ` d 'in turn. It is proved that quadrilateral a ` B ` c ` d' is a square
20. It is known that the upper middle points of AB and BC on both sides of triangle ABC are E.F. two points on AC are G.H. Ag = GH = HC,; Connect and extend EG.FH It is proved that ABCD is a parallelogram;