As shown in the figure, in the known square ABCD, e is the point on ad, BF bisects ∠ EBC intersects DC at point F

Extend Da to g to make Ag = CF
And because AB = CB, & nbsp; angle bag = angle BCF = 90
So triangle AGB is equal to triangle CFB
So Ge = GA + AE = AE + CF
And angle g = angle BFC = angle ABF = angle Abe + angle EBF
=Angle Abe + angle FBC
=Angle Abe + angle GBA = angle GBE
So Ge = be
So be = AE + CF

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