In trapezoidal ABCD, AD / / BC, ab = DC, angle ABC = 80 °, e is the point on lumbar CD, connecting be, AC and AE, if angle ACB = 60 ° and angle EBC = 50 ° Find the degree of the triangle EAC

In trapezoidal ABCD, AD / / BC, ab = DC, angle ABC = 80 °, e is the point on lumbar CD, connecting be, AC and AE, if angle ACB = 60 ° and angle EBC = 50 ° Find the degree of the triangle EAC

Connecting BD with AC and EF, BCF and ADF are all regular triangles,
It can be proved that CB = CE. E, F and B are on the circle with C as the center and CE as the radius, thus the angle EFD = EDF = 40 ° can be proved
Because EF = ed, it is easy to prove triangle ade congruent AFE
So angle CAE = angle DAE = 1 / 2 angle DAC = 30 degree