In the isosceles trapezoid ABCD, the extension lines of AD / / BC, de / / AC and BC intersect at the point E, CA bisects ∠ BCD, and proves ∠ B = 2 ∠ E

In the isosceles trapezoid ABCD, the extension lines of AD / / BC, de / / AC and BC intersect at the point E, CA bisects ∠ BCD, and proves ∠ B = 2 ∠ E

Proof: ∵ de ∥ AC,
∴∠E=∠BCD,
∵ CA bisection ∠ BCD,
∴∠BCD=2∠ACD,
∵AD‖BC,∴∠ACD=∠E,
∵∠B=2∠E,
∴∠BCD=∠B,
The trapezoid ABCD is isosceles trapezoid,
∴AB=DC.