A 60cm long wire is used to form a rectangular area (1) If the width of the rectangle is 2 / 3 of the length, what is the area of the rectangle? (2) If the width of the rectangle is 4cm less than the length, what is the area of the rectangle? (3) If the enclosure is a square, what is the area of the square? (4) Comparing the area relations in (1) (2) (3), what rules can you conclude?

Let the length and width be x and Y respectively. (1) if the width of the rectangle is 2 / 3 of the length, what is the area of the rectangle? X + y = 60 △ 2Y / x = 2 / 3x = 18y = 1218 × 12 = 216 (2) if the width of the rectangle is 4cm less than the length, what is the area of the rectangle? X + y = 60 △ 2x -- y = 4x = 17Y = 1313 × 17 = 221 (3) if the enclosure is a square

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