It is known that the sum of the side lengths of the two squares is 20 cm, the difference between the two squares is 40 cm, and the area of the small square is 40 cm I'm only in the sixth grade, using the knowledge I've learned to answer

It is known that the sum of the side lengths of the two squares is 20 cm, the difference between the two squares is 40 cm, and the area of the small square is 40 cm I'm only in the sixth grade, using the knowledge I've learned to answer

Sum of side length = 20 cm
Then the difference of side length = 40 △ 20 = 2cm
Therefore, the side length of a large square is 11 cm; the side length of a small square is 9 cm
Small square area = 9 × 9 = 81 square centimeter