If the length and width of a square test field are increased by 5 meters, the area will be increased by 825 square meters? The problem of grade four in primary school can not be solved by solving the equation. 825-5*5 =800 square meters 800 / 10 = 80m 80 * 80 = 6400 (M2) Is this calculation correct | Math enthusiast | Mathematical art

If the length and width of a square test field are increased by 5 meters, the area will be increased by 825 square meters? The problem of grade four in primary school can not be solved by solving the equation. 825-55 =800 square meters 800 / 10 = 80m 80 80 = 6400 (M2) Is this calculation correct

Let the original side length be x meters
(x+5)^2 - x^2 = 825
x = 80
The original area is 80 * 80 = 6400 m ^ 2

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