The range of y = log2 (the square of X - 4x + 6) | Math enthusiast | Mathematical art

The range of y = log2 (the square of X - 4x + 6)

Firstly, we consider the definition field x ^ 2-4x + 6 > 0 of this function, and we get x ^ 2-4x + 4 + 2 > 0, that is, (X-2) ^ 2 + 2 > 0
The domain of definition is r
Because x ^ 2-4x + 6, that is, the range of (X-2) ^ 2 + 2 is: [2, + ∞)
So the range of y = log2 (x ^ 2-4x + 6) is [1, + ∞)

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