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首先考慮這個函數的定義域x^2-4x+6>0,得x^2-4x+4+2>0即(x-2)^2+2>0 此時的定義域為R 又因為x^2-4x+6即(x-2)^2+2的值域為:[2,+∞) 所以y=log2(x^2-4x+6)的值域為[1,+∞)
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